Acceleration is (the change is velocity) / (the change in time). That is: for an aircraft that is traveling at velocity V1 at time T1, and is traveling at a velocity V2 at a later time T2, then A=(V2-V1) / (T2-T1)
A speed of 136kts (69.96 meters/sec) to a speed of 48kts (24.69 meters/sec) in a time span of approximately 2.9 seconds. So acceleration = (24.69m/s - 69.96 m/s) / (2.9s) = 15.61 (m/s^2). It is 9.8 m/s^2 to 1 G, so 15.61 (m/s^2) * ((1G)/(9.8 m/s^2)) = 1.59 G
1.59 G
Can somebody double check if it's right?
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